Heat of Reaction Lab

Research Question: What is the heat of reaction of HCl and Magnesium.

 

Abstract: The purpose of this lab was to calculate the heat of reaction is by measuring how much heat was absorbed during the reaction in the 50.0 mL of the 1.0M HCl. In this experiment we used Magnesium and HCl to start the reaction. By putting the HCl and Magnesium in a calorimeter we were able to measure how much heat the HCl absorbed by measuring the starting temperature of it and then measuring the temperature in degrees Celcius every 15 seconds after the reaction had started. We used two calculations to reach our answer. The first one is Q= M x deltaT x SpH. The second one was the enthalpy formula.

Safety: During the lab we wore saftey glasses and kep the lid on the calorimeter because the HCl gives off vapors during the reaction that could irritate our eyes and skin. We also washed our hands immediately after the lab was over.

Materials:

  • Calorimeter
  • Thermometer
  • Magnesium Ribbon
  • 1.0M HCl

Procedure:

  1. The first thing we did was measured out 50 mL of the 1.0M HCl and weighed our empty calorimeter.
  2. Got the mass of the calorimeter + the HCL and then rcorded the starting temp of the HCL with a thermometer
  3.  Cut off about and weighed .18g of Mg ribbon, formed it into a 'ball-like shape' and placed it into the HCl.
  4. Recorded the temperature in degrees Celcius every 15 seconds until the reaction with the Mg and HCl ended.

Evidence:

  • Mass of Calorimteter- 33.18g
  • Mass of Calorimeter+HCl- 82.75g
  • Mass of Mg ribbon- .18g
  • Starting Temp of HCl- 24.4 degrees Celcius

Every 15 Seconds(*Degrees Celcius)

15s- 25.6

30s- 28.0           135s-37.3

45s- 30.3           150s- 37.4

60s- 32.1            Q=2706.52J

75s- 33.8            Heat of Reaction absorbed= 466.25kj

90s- 35.0

105s- 36.0

120s- 36.8

Claim:

466.25kj is the heat of reaction of HCl and Magnesium.

Scientific Explanation:

The purpose of doing this lab was to find out what the heat of reaction of HCL and Mg is. We measured the temp of the HCl while the reaction was going on every 15 seconds so that we could get accurate numbers. The starting temp was 24.4 degrees Celcius. The ending temp was 37.4 degrees Celcius. By putting together all of our data and using the formula Q= M x deltaT x SpH and the enthalpy formula we were able to come to a conclusion that the amount of heat that was produced during the reaction of the HCl and Mg was 466.25kj. To calculate how accurate our answer was we used the percent error formula. By using that formula we calculated that our oercent error was 22.7%.

 

Abstract: The purpose of this lab was to calculate the change in enthalpy by measuring how much heat was absorbed in the water of the calorimeter. In this lab we used magnesium and hydrochloric acid to start the reaction. By containing the hydrochloric acid and the magnesium in a calorimeter we were able to measure how much heat the water absorbed by measuring the temperature with a spark probe every 15 seconds in degrees Celsius. We used two calculations to reach our answer. The first one was Q=M x T x SpH. The second one was the the difference of heat formula. Safety: While doing this experiment we wore safety glasses and kept the lids on the calorimeter because the HCl gives off vapors that could irritate your eyes and skin. We also washed our hands immediately after the experiment was over. Materials: -Calorimeter -Spark Thermometer -magnesium ribbon -1.0 HCl

Biorenewable Paper

The feedback that i got back on my paper was helpful.

One of the things that he said I needed to improve on the most is my introduction. My introduction should have been more clear and understandable.

Instead of focusing on multiple things i should have focused one particular thing.

questions?

1.) what are some useful websites where i could find information about my topic

Serial Dilution Intro

 

 

 Research Question: Usuing colorimetry, how concentrated is a solution in terms of its ability to allow light shine thorugh after a dilution of 1/10 of distilled water added to each solution in a simultaneous order.

Abstract: The reason of this experiment was to get the whole concept of colorimetry. Colorimetry is "quantitative chemical analysis by color using a colorimeter." Our target was to see how much light could pass through a starting solution consisting of 5 mL of liquid bluing and 4.5mL of distilled water. The results of the experiment were sort of obvious because it makes since that little to no light will pass through a solution that has a high concentration and a high percentage of light will pass through a solution that's less concentrated. The highly concentrated solution in test tube #1 allowed 0% of light to pass through. The low concentrated solution in test tube #5 allowed 94.85 of light to pass through.

 

Safety: We wore safety glasses, rolled up our sleeves, and most importantly avoided horse play during this lab. The purpose of the saftey glasses were to our eyes safe from any solution or something that could irritate our eyes. We rolled up our sleeves to avoid stains on our clothing.

Materials:

  • Liquid Bluing---5mL to start with
  • Dilution well plate
  • Plastic dropper
  • Distilled water---4.5mL to start with
  • 10 test tubes
  • Pasco SPARK and Colorimeter
  • Glass cuvettes

Procedure: To begin with we labeled our test tubes 1-10 so that we wouldn't get the solutions mixed up. We placed 5mL of liquid bluing into test tube #1 which is a 100% solution. We then took 12 drops(.5mL) from test tube #1 with a plastic dropper and put it into test tube #2. Once that was done, we used a clean dropper to add 4.5mL of distilled water to the .5mL of the original solution. By doing this we should have had .5mL of the original solution from test tube #1 and 4.5mL of distilled water. We repeated this same process until we got a high reading of light that was passing through the solution.

Evidence:

Concentration:   1x   0.1x     .01x   .001x     .0001x

% transmission: 0%    0%       .8%        49.2%    94.8%

 

Claim: The more concentrated the solution is, the less light passes through. The less concentrated the solution is, more light will pass through.

Scientific Explantion: This lab proves that not alot of light passes through a concentrated solution. I can prove this because in the experiment that we did we used liquid bluing and went through the procedure listed above and the results were pretty much obvious. Not much light can pass through a concentrated solution, and more light can pass through a less concentrated solution. By using a Plasco SPARK device and a Colorimeter our result should be highly accurate. Our results were listed in percentages, so it was a pretty accurate reading. The percentage of light that passed through test tube #1 with a 1x concentraion allowed 0% of light to pass through. It allowed 0% of light because the solution was so dark and there was no way for light to pass through the solution. In test tube #5 with a concentration of .0001x 94.8% of light was allowed to pass through the solution. 94.8% of light was allowed to pass through because the solution had a low concentration and it was almost a clear solution so that meant a large amout of light was able to shine through it. By those results, I think that my claim is well plausible and makes sense.

Quark Blog

--Why has the Standard Model become such an important tool for scientists?

Because scientists can use it to theorize almost everyhting when it comes to particles.

--Explain how subatomic particles are classified. Include information about the properties used to classify.

There's 'Elementary Particles' and 'Composite Particles'. Elementary particles are particles that aren't made out of other particles. The elemetary particles of the standard model are: up, down, bottom, top, strange. charmed, electron, proton, neutrino, muon, tau, and the 13 guage bosons.

--Describe any updates of modifications you could see coming to the Standard Model during your lifetime.

The mass of the Higgs Boson.

Density Column Lab

 Density Lab

Reasearch Question:  In what locations will the given objects be found when dropped into the density column?

Abstract:

In this experiment we were to find out which of the given objects will be found when dropped into the density column. The objects given were: Zine, parafin wax, low density polyethylene, acrylic, a cork, steal, and brass. Basically, we need to weigh all the objects to find out the mass. Once that was done we needed to find out the volume by using water displacement. Once those are recorded we use the formula d=m/v formula to find out the mass.

Safety Considerations:

Keep work area clean

Try not to spill water on the floor

Keep work area dry

No horse play

Materials:

  • Graduated cylinder
  • Given objects
  • Scale
  • Water
  • Pencil
  • Notebook paper

Procedure:

  1. Find out the mass of the given objects
  2. Find the volume of the given objects by using water displacement
  3. d=m/v
  4. Record results

Evidence Collected:

  • Zine: 6.64g/1.00mL
  • Parafin wax: 23.27g/5.05mL=4.61g/mL
  • Low density polyethylene: ???
  • Acrylic: 4.85g/4.90mL=0.99g/mL
  • Cork: 1.22g/8.89mL=0.14g/mL
  • Steal: 31.46g/4.90mL=6.42g/mL
  • Brass:: 34.41g/45.30mL=0.76g/mL
  • Corn Syrup: 1.38g
  • Canola Oil: 0.92g

 

Claim:

  • Top: Canola Oil
  • Middle: Water
  • Bottom: Corn Syrup

Zine, parafin wax, and steal will be found at the bottom. Acrylic would be found in the middle. The cork would be found at the top.

Scientific Explanation:

This is a paragraph that summarizes your findings.  It should explain HOW your evidence supports your claim.  In addition, your scientific explanation needs to draw on information beyond the experiment.  It should speak to larger scientific principles and how they support your overall findings.  It is - as the name suggests - a "science-based" explanation of what you observed or found in the experiment.

Resources:

My notebook with all of the recorded measurements written down.